Originally posted by Nineftfreak
and just for my own vehicle i was told i have a 350 but i have 327 rods in it plus it it bored .60 over so what do i have for c.u. and it my engine still a bored out 350 or do i have to say bored out 327 because of the rods.
Nineftfreak - here's the deal on displacement:

A standard 327 and 350 both have 5.7" rods. So you must mean you have a 327 crank.

Lets assume you have standard 327 crank and rods (5.7"), pistons (.060 over) and a 350 block bored .060 over:

A 350 has a 4" bore.
.060 over (not .60 as thats greater than 1/2 inch) is a 4.060 bore.
Assuming a 327 crank and stock rods and cylinders, your stroke is 3.25".

So the volume of one cylinder is its area*stroke.
Bore = 4.06 (350 bored .060 over)
Stroke = 3.25 (typical 327 stroke)
pi=~3.14 ( a constant value, the ratio of a circle's area as compared to its radius (1/2 diameter or bore) squared)

Area = pi*r*r, where r is 1/2 of the bore (diameter).
Area (of one cylinder) = 3.14*2.03*2.03 = 12.94 (rounded to 2 decimals)
Volume of one cylinder = Area*stroke
Volume of one cylinder = 12.94*3.25 = 42.05 cubic inches (rounded to 2 decimals)
Total volume = Volume of one cylinder * number of cylinders
Total volume = 42.05*8 = 336.4 cubic inches.

Assuming this what you actually have, someone more knowledgeable that I will have to comment on this particular combination's potential.